0=-16t^2+104t+6

Solution for 0=-16t^2+104t+6 equation:

0=-16t^2+104t+6

We move all terms to the left:

0-(-16t^2+104t+6)=0

We add all the numbers together, and all the variables

-(-16t^2+104t+6)=0

We get rid of parentheses

16t^2-104t-6=0

a = 16; b = -104; c = -6;
Δ = b2-4ac
Δ = -1042-4·16·(-6)
Δ = 11200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{11200}=\sqrt{1600*7}=\sqrt{1600}*\sqrt{7}=40\sqrt{7}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-104)-40\sqrt{7}}{2*16}=\frac{104-40\sqrt{7}}{32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-104)+40\sqrt{7}}{2*16}=\frac{104+40\sqrt{7}}{32}
$